Lunar and horary tables, for ... ascertaining the longitude

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Boulter J Bell

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Стр. 70 - C, as seen above, are constants, depending upon the latitude of the place of observation and the declination of the star. Tables for these quantities will be found in an appendix to Annual Report US Coast and Geodetic Survey for 1874.
Стр. 220 - The India Directory; Or, Directions for Sailing to and from the East- Indies, China, Australia, and the interjacent Ports of Africa and South America. Compiled chiefly from Original Journals of the Honourable Company's Ships, and from the Observations and Remarks resulting from the Experience of Twenty-one Years in the Navigation of those Seas. By JAMES HORSBURGH, Esq., FRS, &c.
Стр. 54 - Gamma ; and so on. When the number of stars in a constellation, exceeds the letters in the Greek alphabet, the letters of the Roman alphabet, a, b, c, d, &c. are applied to the remaining stars in the same manner ; and when these are not sufficient, the numbers, 1, 2, 3, 4, 5, &c.
Стр. 56 - Aries, the Ram ; 2. Taurus, the Bull ; 3. Gemini, the Twins ; 4. Cancer, the Crab ; 5. Leo, the Lion ; 6. Virgo, the Virgin ; 7. Libra, the Balance ; 8. Scorpio, the Scorpion; 9. Sagittarius, the Archer ; 10. Capricornus, the Goat; 11. Aquarius, the Water-bearer ; 12. Pisces, the Fishes.
Стр. 9 - ... will be the right ascension of the meridian. From the right ascension of the meridian (increased by 24 hours if necessary) subtract the sun's right ascension...
Стр. 63 - Subtract the true altitude of the sun's centre from 90°, and the remainder will be the sun's true meridian zenith distance, which is to be called north or south according as the observer is north or south of the sun at the time of observation.
Стр. 25 - Rule. — Find the latitudes of both places; if both be north, or both south, their difference will be the answer; but if one be north and the other south, their sum will be the answer. Exercise.— What is the difference of lat. between Philadelphia and Petersburg? Ans., 20 degrees. Between Madras and Waterford? Am., 39° 13'.

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